SOLUTION: csc(θ)=11/8 and the terminal side ofθ is in quadrant II. Find the exact values of the following. No need to rationalize. sin(θ)= cos(θ)= tan(θ)= s

SOLUTION: csc(θ)=11/8 and the terminal side ofθ is in quadrant II. Find the exact values of the following. No need to rationalize. sin(θ)= cos(θ)= tan(θ)= s

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Question 1111724: csc(θ)=11/8 and the terminal side ofθ is in quadrant II. Find the exact values of the following. No need to rationalize.
sin(θ)=
cos(θ)=
tan(θ)=
sec(θ)=
cot(θ)=

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
similar problem.
sin = 1/csc = 8/11

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