SOLUTION: Find the maximum slope of the line tangent to the curve y = -x³+6x²+16x+20.

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Question 1111383: Find the maximum slope of the line tangent to the curve y = -x³+6x²+16x+20.
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
I've seen this problem (with different numbers) at least twice earlier today.
Look at the solved problems.

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Find the maximum slope of the line tangent to the curve y = -x³+6x²+16x+20.
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Slope at every point = -3x^2+12x+16
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To find max slope take the derivative and solve::
-6x+12 = 0
x = 2
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Ans: Max Slope = -3*2^2+12*2+16 = -12 + 24 + 16 = 28
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Cheers,
Stan H.
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