SOLUTION: Find the minimum slope of the line tangent to the curve y = x�-3x�+6x+3.

Question 1111345: Find the minimum slope of the line tangent to the curve y = x�-3x�+6x+3.

Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
derivative of x^3-3x^2+6x+3 is 3x^2-6x+6
The derivative is the slope of the line. The minimum value is where x=-b/2a, like any quadratic.
That is x=6/6=1
The slope is 3-6+6 or 3. The point on the original function is (1, 7)

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