SOLUTION: Find the minimum slope of the line tangent to the curve y = x³-3x²+6x+3.
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Question 1111276: Find the minimum slope of the line tangent to the curve y = x³-3x²+6x+3.
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
The slope of the line tangent to the curve
for each value of is the value of the derivative,
.
is a quadratic polynomial and graphs as a parabola.
You are asked for the minimum value of that expression,
and there are several ways to get to the result.
Can you figure out what way your teacher would favor?
Maybe your teacher expects you to find the minimum of
by looking at
zeros and changes of sign of .
As for ,
for , and
for ,
there is a minimum at .
The minimum slope, for is
.
Alternately, if you memorized class information,
you know that the expression with
has a minimum at .
Maybe your teacher expects you to do that,
find that the minimum is at ,
and calculate that for ,
.
You could just use your algebra knowledge (no memorization)
and "complete the square" like this
As ,
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