SOLUTION: Write the first 5 terms of the sequence: a_(1)=1 a_(2)=0 a_(n)= a_(n-1)-a_(n-2) For a_(3) I got -1 but when I try solving for a_(4) I get -1 again, and for a

SOLUTION: Write the first 5 terms of the sequence: a_(1)=1 a_(2)=0 a_(n)= a_(n-1)-a_(n-2) For a_(3) I got -1 but when I try solving for a_(4) I get -1 again, and for a_(5) I get 2.

Question 1108733: Write the first 5 terms of the sequence:
a_(1)=1
a_(2)=0
a_(n)= a_(n-1)-a_(n-2)
For a_(3) I got -1 but when I try solving for a_(4) I get -1 again, and for a_(5) I get 2.
Key:
a_(#) in words means "a sub #".
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

You should be able to see your mistake if you look at the work you did. Or maybe it would be better to start over on the problem. Often if you make a mistake and try to find it by looking at the work you did, you automatically make the same mistake again.

Here is what you show:
a(1) = 1
a(2) = 0
a(3) = a(2)-a(1) = 0-1 = -1 (looks good)
a(4) = a(3)-a(2) = -1-0 = -1 (still looks good)
a(5) = a(4)-a(3) = -1-(-1) = 2 (how about that one -- does it still look good to you?)
RELATED QUESTIONS
Write the first 5 terms of the sequence: a_(1)=1 a_(2)=0 a_(n)= a_(n-1)-a_(n-2)... (answered by ikleyn)

The sequence is defined recursively. Write the first four terms. {{{a[1]=2... (answered by venugopalramana)

How do I write the first four terms of the sequence? a1=1 and a base n = 3a base... (answered by ewatrrr)

The sequence is defined recursively. Write the first five terms. {{{a[1]=-3}}};... (answered by Edwin McCravy)

Dear Tutor, Could you please explain the procedure in solving this problem: Let... (answered by Fombitz)

Find the first five terms of the sequence. a(1) =�4, a(n+1) =a(n)... (answered by Alan3354)

3, 6, 11, 18 ... The first four terms of a sequence are shown above. Which of the... (answered by Nate)

Please Help!!! I can figure out a) but not b). Can you please explain this to me? Thanks... (answered by Earlsdon)

Suppose that a sequence is defined as follows. a[1] = -1 , a[n] = -3a[n-1]+6 for n... (answered by ewatrrr,solver91311)