SOLUTION: Solve {{{sin(2x)-cos(x)=0}}} given that 0 ≤ x < 2π
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Question 1105276: Solve given that 0 ≤ x < 2π
Found 2 solutions by KMST, rothauserc:
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
is a popular trigonometric identity.
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Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
sin(2x) - cos(x) = 0
:
sin(2x) = cos(x)
:
2sin(x)cos(x) = cos(x)
:
2sin(x) = 1
:
sin(x) = 1/2
:
sin^-1 (1/2) = 30 degrees
:
x = 30 degrees, 150 degrees
:
Note that the sin function is positive in the first and second quadrants
:
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