SOLUTION: While riding her bike to the ocean and back home 55 times, Margaret timed herself at 58⁢min, 54⁢min, 46⁢min, 57⁢min, and 49⁢min. She had set a goal of

Question 1104634: While riding her bike to the ocean and back home 55 times, Margaret timed herself at 58⁢min, 54⁢min, 46⁢min, 57⁢min, and 49⁢min. She had set a goal of averaging 5252 minutes for her rides. How many minutes will she need to spend on her sixth ride to attain her goal?
Answer by greenestamps(13206) (Show Source): You can put this solution on YOUR website!

The easiest way to solve a problem like this, involving an average when all the numbers are close together, is to compare each individual number to the average. The numbers that are over the average have to balance out the numbers that are below the average.

58: +6 compared to the desired average of 52
54: +2
46: -6
57: +5
49: -3

On the first 5 rides, she is a total of 4 minutes over the desired average, so on the 6th ride she needs to be 4 minutes under that average. 52-4 = 48.

She needs to make the 6th ride in 48 minutes to reach her goal of an average time of 52 minutes.
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SOLUTION: While riding her bike to the ocean and back home 55 times, Margaret timed herself at 58&#8290;min, 54&#8290;min, 46&#8290;min, 57&#8290;min, and 49&#8290;min. She had set a goal of

SOLUTION: While riding her bike to the ocean and back home 55 times, Margaret timed herself at 58⁢min, 54⁢min, 46⁢min, 57⁢min, and 49⁢min. She had set a goal of