SOLUTION: A train, traveling at 50 mph., starts 1 and 1/3 hrs. after a slower train, and in 2 hrs., overtakes it. Calculate rate of the slower train. Let x = rate of slower train. rat

Question 1099384: A train, traveling at 50 mph., starts 1 and 1/3 hrs. after a slower train, and in 2 hrs., overtakes it. Calculate rate of the slower train.
Let x = rate of slower train.
rate * time = distance
rate = distance / rate
Faster train: 50 * (t - 1.33)= 50t - 66.5
Slower: x * t = xt.
Not sure how to continue. Non-homework.

Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!

               SPEED       TIME        DISTANCE
FAST           50          2             d
SLOW           r           2+1&1/3       d

FAST train data will give the distance.
SLOW train data will allow to find speed r of the slow train.

------speed of slow train, 30 mph.
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