SOLUTION: Milk and cream contain different percents of butterfat. How much 3% milk needs to be mixed with how much 15% cream to give 20 L of 6%?

Question 1095079: Milk and cream contain different percents of butterfat. How much 3% milk needs to be mixed with how much 15% cream to give 20 L of 6%?
Found 3 solutions by josgarithmetic, ikleyn, greenestamps:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
this video example should help.

15 L of the 3% (milk)
5 L of the 15% (cream)
Answer by ikleyn(52814)   (Show Source): You can put this solution on YOUR website!
.
There are standard procedures/methods to solve such mixture problems.

See introductory lessons covering various types of mixture problems
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
in this site.

Read them and become an expert in solution mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

Answer by greenestamps(13203)   (Show Source): You can put this solution on YOUR website!

one answer that is not an answer but rather a reference to a place where you can see her method of solving the problem; and another answer without any clue to you about how to get that answer....

You can follow the path the first responder gave you, to try a solution by the traditional algebraic method. But give this shortcut method a try and see if you understand it; if you do, you will be able to solve mixture problems like this with much less work.

You are mixing ingredients with butterfat percentages of 3% and 15% to get a mixture of 6% butterfat. Look at how far the 6% is from each of the 15% and 3%:

15-6 = 9
6-3 = 3

The 6% is "3 times as close" to 3% as it is to 15% (because 9 is 3 times as much as 3). That means you need 3 times as much of the 3% milk as you need of the 15% cream.

3 times as much milk as cream and a total of 20 L means 15 L of the 3% milk and 5 L of the 15% cream.
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