SOLUTION: A board that is 53 inches long is to be cut into three pieces. The second piece is twice as long as the first piece, and the third piece is 5 inches longer than three time the firs

Algebra.Com
Question 1093558: A board that is 53 inches long is to be cut into three pieces. The second piece is twice as long as the first piece, and the third piece is 5 inches longer than three time the first piece. Find the length of the three pieces.
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
y=2x
z=3x+5
x+y+z=53
x+2x+3x+5=53
6x+5=53
6x=48
x=8
y=2*8=16
z=(3*8)+5=29

RELATED QUESTIONS

a 56-inch board is to be cut into three pieces so that the second piece is twice as long... (answered by jorel1380,rsteph4289)
a 48 inch board is to be cut into three pieces so that the second piece is twice as long... (answered by macston)
A 40-inch board is to be cut into three pieces so that the second piece is twice as long... (answered by Cromlix)
a 49inch board is to be cut into three pieces so that the second piece is twicw as long... (answered by solver91311,macston)
A ​24-inch board is to be cut into three pieces so that the second piece is twice as... (answered by josgarithmetic)
A 56​-inch board is to be cut into three pieces so that the second piece is twice as... (answered by math_tutor2020)
a 49inch board is to be cut into three pieces so that the second piece is twice as long... (answered by solver91311)
A 24inch board is to be cut three into three pieces so that the second piece is twice as (answered by macston)
A 32-inch board is to be cut into three pieces so that the second piece is three times as (answered by Cromlix)