SOLUTION: George and Dale have been assigned the same number of math problems for homework. George has finished 22 problems, and Dale has finished 6 problems. If dale has three times as many

Question 1093467: George and Dale have been assigned the same number of math problems for homework. George has finished 22 problems, and Dale has finished 6 problems. If dale has three times as many problems remaining as George does, how many problems was George originally assigned?
Answer by ikleyn(52777) (Show Source): You can put this solution on YOUR website!
.

Let the integer number N be the total number of problems assigned to each separately.


When George solved 22 problems,  (N-22) problems remained to solve.

When Dale solved 6 problems,  (N-6) problems remained to solve.


The condition says that

N-6 = 3*(N-22).


Simplify and solve:

N - 6 = 3N - 66,

66 - 6 = 3N - N,

2N = 60  ====>  N =  = 30.


Answer.  In all, 30 problems were assigned to each.


Check.   Please make check on your own.

Nice problem !

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