SOLUTION: How many liters containing 8% acid solution should be added to 20 liters containing 60% acid in order to obtain a 40% acid solution?

Question 1093330: How many liters containing 8% acid solution should be added to 20 liters containing 60% acid in order to obtain a 40% acid solution?

Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
How many liters containing 8% acid solution should be added to 20 liters containing 60% acid in order to obtain a 40% acid solution?
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Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
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101-th time:

= 0.4. The numerator is the volume of the pure acid in the mixture, obtained by adding the volumes of the pure acid in components; the denominator is the total liquid volume. x is the unknown volume under the question. Simplify and solve for x.

For details, many other samples and examples of solved mixture problems see the lessons
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
in this site.

Read them and become an expert in solution mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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