SOLUTION: A rock is tossed straight up with initial velocity of 10 feet per second from atop a balcony 30 ft above the ground. The height of the rock is given by the equation h(t) = -16t^2 +
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Question 1093126: A rock is tossed straight up with initial velocity of 10 feet per second from atop a balcony 30 ft above the ground. The height of the rock is given by the equation h(t) = -16t^2 + 10t + 30 at a time t seconds after the rock was tossed. How many seconds pass before the rock is 20 feet above ground?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Since the rock is tossed from a height above
20 ft, then the rock will be falling at 20 ft
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Use quadratic formula
sec
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check answer:
here's the plot:
Looks about right
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