SOLUTION: Franz intends to mix a solution containing 11% sugar with 24 miligrams of a solution containing 20% sugar. He is hoping to create a mixture that contains 15% sugar. How many millig
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Question 1089517: Franz intends to mix a solution containing 11% sugar with 24 miligrams of a solution containing 20% sugar. He is hoping to create a mixture that contains 15% sugar. How many milligrams of the 11% solution must he use?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Franz intends to mix a solution containing 11% sugar with 24 miligrams of a solution containing 20% sugar.
He is hoping to create a mixture that contains 15% sugar.
How many milligrams of the 11% solution must he use?
:
let x = amt of 11% solution
A typical mixture equation
.20(24) + .11x = .15(x+24)
4.8 + .11x = .15x + 3.6
4.8 - 3.6 = .15x - .11x
1.2 = .04x
x = 1.2/.04
x = 30 mg of the 11% solution required
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