SOLUTION: ``The size P of a certain insect population at time t​ (in days) obeys the function P(t)=700e^0.05t
​(a) Determine the number of insects at t=0 days.
​(b) W
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Question 1088640: ``The size P of a certain insect population at time t (in days) obeys the function P(t)=700e^0.05t
(a) Determine the number of insects at t=0 days.
(b) What is the growth rate of the insect population?
(c) What is the population after 10 days?
(d) When will the insect population reach 1050?
(e) When will the insect population double?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
P(0)=700e^0=700.
growth rate is 0.05 or 5%
after 10 days 700*e^0.5
1154.10 or 1154 after 10 days.
=======================
1050=700e^(0.05t)
divide by 700
1.5=e^0.05t
ln both sides
ln 1.5=0.05 t
8.11 days.
=======================
doubling time crudely is rule of 72, where 72/5 is about 14.
1400=700e^0.05t
2=e^0.05t
ln2=0.05t
13.86 years.
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