SOLUTION: A brass disc has the following dimensions; Diameter; 6'5" Thickness; 4" 5 4" holes. Brass weighs .3 lbs. / cu. in. Determine weight. Volume of cylinder; pi * r^2

Question 1088573: A brass disc has the following dimensions;
Diameter; 6'5"
Thickness; 4"
5 4" holes.
Brass weighs .3 lbs. / cu. in.
Determine weight.
Volume of cylinder; pi * r^2 * h.
3.1416 * 38.5 * 38. 5 * 4 = 18626.5464 cu. in. (total vol.)
3.1416 * 2 * 2 * 4 = 50.2656 cu. in. (vol. of 1 hole).
50.2656 * 5 = 251.328 cu. in. (vol. of 5 holes).
18626.5464 - 251.328 = 18375.2184 cu. in. (net vol.)
18375.2184 * .3 = 5512.56522 lbs.
Where am I incorrect? Non-homework.

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
I'll take a slightly different approach
[ net vol ] = [ net area ] x [ height ]
in
in

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------------------------------
net volume
and
lbs weight
----------------------------------------
check my math & formulas

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