SOLUTION: Fred is twice as old as Bob. Kim is 2 years older than Bob. Jane is 5/4 as old as Kim. Tim is one fourth as old as Jane. Vanessa is four years older than Tim. Miguel is 3 year

Question 1084967: Fred is twice as old as Bob.
Kim is 2 years older than Bob.
Jane is 5/4 as old as Kim.
Tim is one fourth as old as Jane.
Vanessa is four years older than Tim.
Miguel is 3 years younger than Vanessa.
Phillip is 3 times as old as Miguel.
Phillip's wife is 3 years younger than he is.
Phillip's son's age is one fifth of Phillip's wife.
His daughter is one third the age of his son.
Fred is 60.

Found 2 solutions by MathTherapy, MathLover1:
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
You found time to write/copy and paste all of this, but omitted the most important thing? I'll leave you to determine what that is!!
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
Fred is twice as old as Bob -> ->
Kim is 2 years older than Bob->
Jane is 5/4 as old as Kim ->
Tim is one fourth as old as Jane ->
Vanessa is four years older than Tim->
Miguel is 3 years younger than Vanessa->
Phillip is 3 times as old as Miguel ->
Phillip's wife ( ) is 3 years younger than he is->
Phillip's son's age () is one fifth of Phillip's wife.->
His daughter () is one third the age of his son.->
Fred is .->
so, if than ->
if Kim -> ->
if Jane is -> -> ->
if Tim is -> ->
if Vanessa is->->
if Miguel is -> ->
if Phillip is ->->
if Phillip's wife is -> ->
if Phillip's son's is ->->
if his daughter is ->->

so, we know that:
Fred is
Bob is
Kim is
Jane is
Tim is
Vanessa is
Miguel is
Phillip is
Phillip's wife is
Phillip's son is
and his daughter is

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