Question 1082951: What is the percentatge error made in the computed surface are of a sphere if the error made in measuring the radius is 3%.
Found 2 solutions by Boreal, MathTherapy:Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website! It would be (1.03)^3=1.093=9.3%
check with a sphere of radius 2 and 2.06
Volume is pi*2.06^3*(4/3) divided by pi*2^3*(4/3)=8.74/8=1.093 or 9.3%