SOLUTION: I'm having trouble interpreting this word problem. I don't know how to set up an equation for it, but I will be fine once I know what the equation is. Here's the problem: "Last sat

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Question 1082648: I'm having trouble interpreting this word problem. I don't know how to set up an equation for it, but I will be fine once I know what the equation is. Here's the problem: "Last saturday night, the entire gargantuan clan went to see the box-office smash 'It loves me; it loves me not'. Tickets cost $6 for adults and $3.50 for children. If 124 people attended the show and the theatre sold $679 worth of tickets, how many adults attended?" I would appreciate if you could get back to me as soon as possible.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39623)   (Show Source): You can put this solution on YOUR website!
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Tickets cost $6 for adults and $3.50 for children. If 124 people attended the show and the theatre sold $679 worth of tickets, how many adults attended?"
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c, children attended
a, adults attended

, accounts how many attended
, accounts for ticket sales

Question asks just for number of adults.

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Answer by ikleyn(52835)   (Show Source): You can put this solution on YOUR website!
.
It is very standard problem.

Solution #1 (using a system of two equations)

 a +    c = 124,    (1)    ("attendie" equation)
6a + 3.5c = 679.    (2)    {"value" equation)

Here, as you can guess, "a" stands for the number of adults and "c" stands for the number of children.


From (1), express a = 124-c, and substitute it into (2). You will get

6*(124-c) + 3.5c = 679.


This is a single equation for c.

If the data is correct, it has an integer solution.

You can solve it on your own.
Let it be an exercise to empower you brain.


Solution 2 (Using one single equation)

Let "c" be the number of children. 
Then the number of adult is (124-c).

Then you can write a "value equation

6*(124-c) + 3.5c = 679.


Notice that it coincides with the equation of the Solution 1.


Again, you can complete the solution on your own.

Happy learning !!


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