SOLUTION: carol,ava and cindy swim at a public pool each day . one day carol swam twice as many laps as ava and cindy swam three more laps than ava. if the women swam 27 laps together, how m

Question 108217: carol,ava and cindy swim at a public pool each day . one day carol swam twice as many laps as ava and cindy swam three more laps than ava. if the women swam 27 laps together, how many laps did each swim?
Answer by elima(1433) (Show Source): You can put this solution on YOUR website!
carol,ava and cindy swim at a public pool each day . one day carol swam twice as many laps as ava and cindy swam three more laps than ava. if the women swam 27 laps together, how many laps did each swim?
=========================
x=carol
y=ava
z=cindy
==============
x=2y
z=y+3
=============
x+y+z=27
2y+y+y+3=27
4y+3=27
4y=27-3
4y=24
y=6
=============
So Ava swam 6 laps
Carol = 2(6)=12
Cindy=6+3=9
:)
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