SOLUTION: A ball is thrown downward from the top of a 130​-foot building with an initial velocity of 29 feet per second. The height of the ball h after t seconds is given by the equati
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Question 1079293: A ball is thrown downward from the top of a 130-foot building with an initial velocity of 29 feet per second. The height of the ball h after t seconds is given by the equation.h= −16t2−29t+130. How long after the ball is thrown will it strike the ground?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
h= −16t2−29t+130
When h = zero.
−16t2−29t+130 = 0
Solve for t.
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