SOLUTION: SOLVING APPLICATIONS Assume that a water rocket is launched upward with initial velocity of 12 ft/sec. Its height h, in feet, after t seconds, is given

Question 1065995: SOLVING APPLICATIONS
Assume that a water rocket is launched upward with initial velocity of 12 ft/sec. Its height h, in feet, after t seconds, is given by H=12t-16ft^2 Determine the height of the rocket one 1/2 sec after it has been launched.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
-16t^2+12t=H(t)
H(0.5)=-4+6=2 feet.

maximum height at -12/-32 or 3/8 second (2.25 feet)
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SOLUTION: SOLVING APPLICATIONS Assume that a water rocket is launched upward with initial velocity of 12 &#8203;ft/sec. Its height&#8203; h, in&#8203; feet, after t&#8203; seconds, is given

SOLUTION: SOLVING APPLICATIONS Assume that a water rocket is launched upward with initial velocity of 12 ft/sec. Its height h, in feet, after t seconds, is given