SOLUTION: two candles of equal length are lit at the same time. one candle takes 6 hours to burn out and the other takes 3 hours. After how much time will the slower burning candle be exactl

Question 1065529: two candles of equal length are lit at the same time. one candle takes 6 hours to burn out and the other takes 3 hours. After how much time will the slower burning candle be exactly twice as long as the faster burning one?

Answer by ikleyn(52787) (Show Source): You can put this solution on YOUR website!
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two candles of equal length are lit at the same time. one candle takes 6 hours to burn out and the other takes 3 hours.
After how much time will the slower burning candle be exactly twice as long as the faster burning one?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Faster candle rate of burning is  of its length per hour.

Slower candle rate of burning is  of its length per hour.

The length of the remaining part for the faster candle is  after t hours.

The length of the remaining part for the slower candle is  after t hours.

The question asks about time t when Slower(t) = 2*Faster(t), or

 =  .


To solve for t, multiply both sides by . You will get

 = ,   or

12 - 4t = 6 - t  --->  12 - 6 = 4t - t  --->  6 = 3t  --->  t = 2.

Answer. After 2 hours.

If you have questions or want to say "thanks", then please mention the ID number of this problem (# 1065529) in your response.

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