SOLUTION: Franklin has $3.95 in nickels, dimes, and quarters. If he has three times as many dimes as quarters, and five fewer nickels than dimes, how many coins of each type does he have?

Question 1065240: Franklin has $3.95 in nickels, dimes, and quarters. If he has three times as many dimes
as quarters, and five fewer nickels than dimes, how many coins of each type does he
have?
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
d = 3q
since d = 3q and nickels = dimes-3, we can say:
n = 3q-5
. - . - . - . - . - .
0.05n+0.10d+0.25q = 3.95 substitute per above:
0.05(3q-5)+0.10(3q)+0.25q = 3.95
0.15q-0.25+0.30q+0.25q = 3.95
group:
0.15q+0.30q+0.25q-0.25 = 3.95
0.7q = 4.20
q = 6 Franklin has 6 quarters
and
d = 3q = 3(6) = 18 he has 18 dimes
you do the nickels
:
John
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