SOLUTION: the square has 2 inches added to its length and 1 inch added to its width, creating an area of 42 inches , find the length of the of the original square
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Question 1064855: the square has 2 inches added to its length and 1 inch added to its width, creating an area of 42 inches , find the length of the of the original square
Found 2 solutions by ikleyn, math_helper:
Answer by ikleyn(52785) (Show Source): You can put this solution on YOUR website!
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5 inches.
Answer by math_helper(2461) (Show Source): You can put this solution on YOUR website!
Length of each side = x
{{[ (x+2)(x+1) = 42 }}}
x = 5 or x = -8 (discard -8 b/c length must be > 0)
If x = 5, (x+2)(x+1) = (7)(6) = 42 (ok)
Ans: x=in
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Also, area of a square is always in (unit)^2: e.g. not inches.
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