SOLUTION: Becky and Rita are 648 miles apart. Becky walks toward Rita at the rate of 2.25 m/s and Rita runs towards Becky. What is Rita's average speed if she reaches Becky in 1.6 minutes?

Question 106367: Becky and Rita are 648 miles apart. Becky walks toward Rita at the rate of 2.25 m/s and Rita runs towards Becky. What is Rita's average speed if she reaches Becky in 1.6 minutes?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Becky and Rita are 648 miles apart. Becky walks toward Rita at the rate of 2.25 m/s and Rita runs towards Becky. What is Rita's average speed if she reaches Becky in 1.6 minutes?
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Comment: I don't know if your 2.25 m/s is meters/second or 2.25 miles/second
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Becky DATA:
Rate = 2.25 miles/sec ; distance = x miles ; time = d/r = x/2.25 seconds
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Rita DATA:
Time = 96 seconds ; distance = 648-x miles ; rate = d/t = (648-x)/96 miles/sec.
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EQUATION:
Becky time = Rita time
x/2.25 = 96
x = 216 miles (Becky's distance)
Rita's speed = (648-216)/96 = 432/96 = 4.5 miles/second
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Cheers,
Stan H.

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