SOLUTION: A parcel of land covers 43,560 sq. ft. The parcel is to be divided into 5 lots which 2 are of the same size and 3 are smaller. The larger are 5/4 as large as the smaller. Determ

Question 1063503: A parcel of land covers 43,560 sq. ft. The parcel is to be divided into 5 lots which 2 are of the same size and 3 are smaller. The larger are 5/4 as large as the smaller. Determine lot area.
My partial attempt:
43560 sq. ft. = acre.
Let A, B, C, D, E be lots.
A = B.
C + D + E = A + B + 1.25
Unsure how to proceed. Non-homework.
Thanks.

Found 2 solutions by Boreal, josgarithmetic:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
C=D=E are x, and their area is 3x
A=B are (5/4)x, and their area is (5/2)x
Their sum is 43,560 =(11/2)x
multiply by (2/11) both sides
x=43560(2/11)=7920 sq ft.
3 of them is 23,760 sq ft.
The larger are 5/4 as large or 9900 sq ft
2 of them are 19,800 sq ft.
The sum is 43,560 sq ft.
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
*Simpler method shown below at bottom

x, the two larger sized lots area together
y, the three smaller sized lots area together

and

Solve that as a system for x and y.
You are interested then in , the size of each of the larger lots and , the size of each of the three smaller lots.

NOT THE ONLY WAY

* This may be simpler.
s, size of each small lot
b, size of each big lot

Solve this system for s and b.
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