SOLUTION: Joe has been playing hockey 2 years more than twice as long as his brother Al. The sum of their years of experience is one. How many years has each boy been playing?

Question 1063376: Joe has been playing hockey 2 years more than twice as long as his brother Al. The sum of their years of experience is one. How many years has each boy been playing?
Found 3 solutions by stanbon, addingup, MathTherapy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Joe has been playing hockey 2 years more than twice as long as his brother Al. The sum of their years of experience is one. How many years has each boy been playing?
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J = A + 2
J + A = 1
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No positive solution.
Please check your post.
Cheers,
Stan H.
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Answer by addingup(3677)   (Show Source): You can put this solution on YOUR website!
J = 2A+2 we'll use this value for J next
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J+A = 1 substitute for J
2A+2+A = 1
3A = -1
A = -1/3
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Check:
2A+2+A = 1
2(-1/3)+2+-1/3 = 1
-2/3+-1/3+2 = 1 add -2/3+-1/3 and you get -1:
-1+2 = 1
1 = 1 Correct
:
John

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Joe has been playing hockey 2 years more than twice as long as his brother Al. The sum of their years of experience is one. How many years has each boy been playing?

DOESN'T MAKE sense!!
How can one have experience that is 2 years more than twice that of the other, and the sum of their years of experience is 1? Absolutely RIDICULOUS!!
A person attempted it and got years. What is years' experience? Where did some of these people learn math?
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