SOLUTION: A colony of bacteria increases by 1 % each day. If there were 2.4 million bacteria on day 5, how many million bacteria will there be on day 17?

Question 1062302: A colony of bacteria increases by 1 % each day. If there were 2.4 million bacteria on day 5, how many million bacteria will there be on day 17?
Found 2 solutions by stanbon, Alan3354:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A colony of bacteria increases by 1 % each day. If there were 2.4 million bacteria on day 5, how many million bacteria will there be on day 17?
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If day 5 has 2.4 mil, day 17 is 12 days later.
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A(17) = 2.4*1.01^12 = 2.7 million
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Cheers,
Stan H.
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Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A colony of bacteria increases by 1 % each day. If there were 2.4 million bacteria on day 5, how many million bacteria will there be on day 17?
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b0 = # on day zero
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b = b0*1.01^t
2.4 = b0*1.01^5
b0 = 2.4/(1.01^5)
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On day 17:
b = b0*1.01^17 = 1.01^17*2.4/(1.01^5) = 2.4*1.01^12
b = 2.70438 million

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