SOLUTION: Find three consecutive natural numbers such that the square of the smallest number is 65 less than the product of the remaining two numbers.

SOLUTION: Find three consecutive natural numbers such that the square of the smallest number is 65 less than the product of the remaining two numbers.

Algebra.Com

Question 1061060: Find three consecutive natural numbers such that the square of the smallest number is 65 less than the product of the remaining two numbers.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Let the three numbers be N-1, N, and N+1.

So the numbers are 21,22, and 23.
Verifying,

True, good solution.

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