SOLUTION: Ref. Question 1055341;
Just for info:
Answers given with problem => x = .22 cu. yds. of cement, y = .44 cu. yds. of sand (y = 2x), z = .88 cu. yds. of gravel(z = 4x).
My
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Question 1055349: Ref. Question 1055341;
Just for info:
Answers given with problem => x = .22 cu. yds. of cement, y = .44 cu. yds. of sand (y = 2x), z = .88 cu. yds. of gravel(z = 4x).
My question: How did they obtain .22 for x ? Thanks again.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
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