SOLUTION: Hi Ken and Ivan had some sweets. After ken gave away 5/7 of his sweets, he had 2/3 as many as ivan. ivan then gave away 120 sweets and he had 1/4 as many sweets as ken. How many

Question 1051843: Hi
Ken and Ivan had some sweets. After ken gave away 5/7 of his sweets, he had 2/3 as many as ivan.
ivan then gave away 120 sweets and he had 1/4 as many sweets as ken. How many did each have at first.
thanks
Found 3 solutions by josgarithmetic, MathTherapy, advanced_Learner:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
MISTAKE FOUND*

Ken has x sweets.
Ivan has y sweets.

ken gave away 5/7 of his sweets, he had 2/3 as many as ivan.

ivan then gave away 120 sweets and he had 1/4 as many sweets as ken.

Simplify each equation.
-

-
* -------------MISTAKE HERE! Ruins the rest of the work.

-
Substitute for x.

Solve this for y.

---------------This makes no sense. y would be negative.

* MISTAKE IDENTIFIED; solution process not yet corrected
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Hi
Ken and Ivan had some sweets. After ken gave away 5/7 of his sweets, he had 2/3 as many as ivan.
ivan then gave away 120 sweets and he had 1/4 as many sweets as ken. How many did each have at first.
thanks

At first,
Answer by advanced_Learner(501)   (Show Source): You can put this solution on YOUR website!
Hi
Ken and Ivan had some sweets. After ken gave away 5/7 of his sweets, he had 2/3 as many as ivan.
ivan then gave away 120 sweets and he had 1/4 as many sweets as ken. How many did each have at first.
thanks

=
=
first part
=
=
=
second part
=
=

Solved by pluggable solver: Linear System solver (using determinant)

Solve:

Any system of equations:

has solution

or

(k=336, I=144}

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