SOLUTION: Ref. Question 1051556:
"The area of each hexagon is ~ 2338 sq ft
Area = ns^2*cot(180/n)/4 where n = # of sides and s = side length.
---
43560/2338 =~ 18.63 hexagons
Ea
Algebra.Com
Question 1051632: Ref. Question 1051556:
"The area of each hexagon is ~ 2338 sq ft
Area = ns^2*cot(180/n)/4 where n = # of sides and s = side length.
---
43560/2338 =~ 18.63 hexagons
Each hexagon is 7 trees, but 6 of them are part of 3 different hexagons "
I don't understand these steps. Thanks.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Ref. Question 1051556:
"The area of each hexagon is ~ 2338 sq ft
Area = ns^2*cot(180/n)/4 where n = # of sides and s = side length.
---
That's the area of a hexagon with sides of 30 feet.
---
43560/2338 =~ 18.63 hexagons
18.63 = area of 1 acre/2338
========================================
Each hexagon is 7 trees, but 6 of them are part of 3 different hexagons
----
That got messy. It was easier to count the trees for 19 hexagons than to try to figure it out that way.
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