SOLUTION: Player A led a baseball league in runs batted in for the 2006 regular season. Player B, who came in second to player A had 10 fewer runs batted in for the 2006 regular season. Toge

Question 1049824: Player A led a baseball league in runs batted in for the 2006 regular season. Player B, who came in second to player A had 10 fewer runs batted in for the 2006 regular season. Together these two players brought home 232 runs during the season. How many runs batted did player A and B each account for?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Player A led a baseball league in runs batted in for the 2006 regular season. Player B, who came in second to player A had 10 fewer runs batted in for the 2006 regular season. Together these two players brought home 232 runs during the season. How many runs batted did player A and B each account for?
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B = A -10
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A + B = 232
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Substitute::
A + A-10 = 232
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2A = 242
A = 121 runs
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B = A - 10
B = 111 runs
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Cheers,
Stan H.
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