SOLUTION: If 4A = I and 8A = U, show algebraically the number of I's needed to equal one U.

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Question 1044855: If 4A = I and 8A = U, show algebraically the number of I's
needed to equal one U.
Found 3 solutions by josgarithmetic, Edwin McCravy, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
Answer by Edwin McCravy(20060)   (Show Source): You can put this solution on YOUR website!
If 4A = I and 8A = U, show algebraically the number of I's
needed to equal one U.
Let n = the number of I's needed to equal one U.

Then

nI = U

Substitute 4A for I and substitute 8A for U

n(4A) = 8A

Solve for n:

Simplifying:

4nA = 8A

Divide both sides by 4A





So we need 2 I's to equal one U.

Edwin
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

If 4A = I and 8A = U, show algebraically the number of I's
needed to equal one U.
8A =  U

2(4A) = U

2I = U ----- Substituting I for 4A

 

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