SOLUTION: Hi tutors here at algebra.com you've made my day happy. I just wanna ask this problem: " A car travels 60 miles in the same time that a car travelling 10 miles per hour faster t

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Question 1044581: Hi tutors here at algebra.com you've made my day happy. I just wanna ask this problem:
" A car travels 60 miles in the same time that a car travelling 10 miles per hour faster travels 90 miles. What is the rate of each car?"
Thanks for answering this problem
Found 3 solutions by josgarithmetic, ikleyn, MathTherapy:
Answer by josgarithmetic(39627)   (Show Source): You can put this solution on YOUR website!
Travel Rates Rule, RT=D to relate rate, time, distance. 

               RATE        TIME       DISTANCE

SLOWCAR        r           t          d

FASTCAR       r+k          t          D
















--------purely symbolic formula answer. Use the assigned values to evaluate r.
Answer by ikleyn(52864)   (Show Source): You can put this solution on YOUR website!
.
Hi tutors here at algebra.com you've made my day happy. I just wanna ask this problem:
" A car travels 60 miles in the same time that a car travelling 10 miles per hour faster travels 90 miles. What is the rate of each car?"
Thanks for answering this problem
~~~~~~~~~~~~~~~~~~~~ 

Your equation is

 = ,

where "u" is an unknown rate/speed of the car in the first scenario.

Multiply both sides by . You will get

2*(u+10) = 3u,  or

2u + 20 = 3u,  or

20 = 3u - 2u,  or

u = 20.

Answer.  The rate of the 1-st car is 20 mph. The rate of the second car is 30 mph.

Be happy.


Answer by MathTherapy(10556)   (Show Source): You can put this solution on YOUR website!
Hi tutors here at algebra.com you've made my day happy. I just wanna ask this problem:
" A car travels 60 miles in the same time that a car travelling 10 miles per hour faster travels 90 miles. What is the rate of each car?"
Thanks for answering this problem 
Let speed (rate) of slower car be S

Then speed (rate) of faster car = S + 10

Time slower car takes to cover 60 miles: 

Time faster car takes to cover 90 miles: 

We then get the following TIME equation: 

90S = 60(S + 10)------ Cross-multiplying

90S = 60S + 600

90S - 60S = 600

30S = 600

S, or speed (rate) of slower car = , or  

Add 10 to this speed (rate) to get speed (rate) of faster car. 

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