SOLUTION: A plane took 1 hour longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion, wh

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Question 104359: A plane took 1 hour longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion, what was the flying time for the second part of the trip?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A plane took 1 hour longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion, what was the flying time for the second part of the trip?
:
Let t = time required for the 2nd part of the trip
Then
(t+1) = time required for the 1st part
:
It said the speed was the same, write a simple speed equation:
Speed = Dist/time
:
1st part speed = 2nd part speed
560%2F%28%28t%2B1%29%29 = 480%2Ft
Cross multiply and you have
560t = 480(t+1)
560t = 480t + 480
560t - 480t = 480
80t = 480
t = 480/80
t = 6 hrs for the 2nd part of the trip
:
Check solution by finding the speed of each portion of the trip;
1st part required 7 hrs
560%2F7 = 80
480%2F6 = 80
:
Kind of slow for a plane, but it checks out.