SOLUTION: At a party, colas , squash and fruit juice were offered to guests. A fourth of the guests drank colas , a third drank squash , two fifths drank fruit juice and just three did not d

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Question 1042908: At a party, colas , squash and fruit juice were offered to guests. A fourth of the guests drank colas , a third drank squash , two fifths drank fruit juice and just three did not drink anything. How many guests were there in all ?
Found 3 solutions by ikleyn, macston, MathTherapy:
Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
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At a party, colas , squash and fruit juice were offered to guests. A fourth of the guests drank colas ,
a third drank squash , two fifths drank fruit juice and just three did not drink anything. How many guests were there in all ?
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x - 3 = ,

x - 3 = ,

x - 3 =  = ,

 =   --->  x = 60*3 = 180.

Answer. 180 guests.


Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
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x=number of guests
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0.25x+0.3333x+0.4x+3=x
0.9833x+3=x
3=0.0100x
300=x
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ANSWER: There were 300 guests.
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Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

At a party, colas , squash and fruit juice were offered to guests. A fourth of the guests drank colas , a third drank squash , two fifths drank fruit juice and just three did not drink anything. How many guests were there in all ?
Let number of guests be G
Then:

15G + 20G + 24G + 180 = 60G -------- Multiplying by LCD, 60
59G + 180 = 60G
180 = 60G - 59G
G, or number of guests =
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