SOLUTION: Two trains start from towns 224 mi apart and travel towards each other on parallel tracks. They pass each other 1.6 hr later. If one train travels 10 mph faster than the​ oth

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Question 1040175: Two trains start from towns 224 mi apart and travel towards each other on parallel tracks. They pass each other 1.6 hr later. If one train travels 10 mph faster than the​ other, find the speed of each train.
The speed of the slower train?
the speed of the faster train?
Answer by ikleyn(52863)   (Show Source): You can put this solution on YOUR website!
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Two trains start from towns 224 mi apart and travel towards each other on parallel tracks.
They pass each other 1.6 hr later. If one train travels 10 mph faster than the​ other, find the speed of each train.
The speed of the slower train?
the speed of the faster train?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

Let x be he speed of the slower train, in mph (miles per hour).
Then the speed of the other train is (x+10) mph, according to the condition.

Your equation is 

1.6x + 1.6*(x+10) = 224.

Why? - The first addend in the left side is the distance covered by the slower train.
The second addend in the left side is the distance covered by the faster train.
The sum is 224 miles, because they together covered all the distance to the moment when they meet each other.

Now solve this equation. It is simple, and you can easily do it on your own.

On Travel and distance problems see the lesson  Travel and Distance problems  in this site and many others associated with it.


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