SOLUTION: The equation h=-16tē + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground.
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Question 103474: The equation h=-16tē + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180 ft.
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
180=-16t^2+112t
16t^2-112t+180=0
(4t-18)(4t-10)=0
4t-18=0
4t=18
t=18/4
t=4.5 answer.
4t-10=0
4t=10
t=10/4
t=2.5 answer.
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