SOLUTION: Three integers have a sum of 50. The second integer is four times as large as the first inteer and the third integer is 4 less than the second integer. What are the three integers?

SOLUTION: Three integers have a sum of 50. The second integer is four times as large as the first inteer and the third integer is 4 less than the second integer. What are the three integers?

Algebra.Com

Question 1034127: Three integers have a sum of 50. The second integer is four times as large as the first inteer and the third integer is 4 less than the second integer. What are the three integers?
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
f + 4f + (4f - 4) = 50
==> 9f - 4 = 50
==> 9f = 54
==> f = 6, the first integer,
4f = 24, the second integer, and
4f - 4 = 20, the third integer.
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