SOLUTION: The manager of a store selling tea plans to make a mix using a mix of a more expensive tea that costs $8 per pound and a less expensive tea that costs $3 per pound to create a 130-

Question 1034043: The manager of a store selling tea plans to make a mix using a mix of a more expensive tea that costs $8 per pound and a less expensive tea that costs $3 per pound to create a 130- pound blend that will sell for 5$ a pound how many of each type are required>?
Found 2 solutions by fractalier, jorel555:
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the amount of $8 tea, x.
Then the amount of $3 tea would be 130-x.
The setup looks like this:
8x + 3(130-x) = 5(130)
Now solve for x...
8x + 390 - 3x = 650
5x = 260
x = 52 lbs @ $8 so that
130-x = 78 lbs @ $3
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let x = amount of $8 per pound tea; Then:
8(x)+3(130-x)=5(130)
8x+390-3x=650
5x=260
x=52
130-x=78
52 lbs. of $8 tea plus 78 lbs of $3 tea equals 130 lbs. of $5 tea!!!!!
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