SOLUTION: A ball is thrown into the air with an upward velocity of 48ft/s it's high eight in feet after T seconds is given by the function h=-16t^2+48x+6. How long does it take the ball to

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Question 1032888: A ball is thrown into the air with an upward velocity of 48ft/s it's high eight in feet after T seconds is given by the function h=-16t^2+48x+6. How long does it take the ball to reach its maximum height ? What is the balls maximum height ? Round to the nearest hundredth of necessary
Answer by Edwin McCravy(20062)   (Show Source): You can put this solution on YOUR website!

If a projectile is thrown into the air with an upward velocity of
v0, its height in feet after t seconds is given by the function 

   ht = -16t2+v0x+h0. 

to find the time when it reaches its maximum height, use the
vertex formula:

         t = -b/(2a) or -v0/(2*-16)

to find the maximum height, substitute that value of t into

   ht = -16t2+v0x+h0 

Edwin
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