SOLUTION: There are x boys and y girls in a class (class A). The girls outnumber the boys by 4. They join up with another class (class B) in which there are twice as many boys as girls. Clas

Question 1030934: There are x boys and y girls in a class (class A). The girls outnumber the boys by 4. They join up with another class (class B) in which there are twice as many boys as girls. Class B has 3 more boys and 5 less girls than class A. Which systems of equations can be used to solve for x and y?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x=boys in A
y=girls in A
y-4=x or -x=y-4
Class A has y-4+y students or 2y-4
2x+y is B
x+3 boys and y-5 girls.
But in B x+3=2(y-5)
x=2y-13
x-y-4 rom above.
-x=-y+4 add them
0=y-9
y=9
x=5
Class A has 5 boys and 9 girls
Class B has 8 boys and 4 girls, which is twice as many.

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