The helicopter could fly at 4 times the speed of the wind. Thus, it could travel 600 miles downwind in 1 hour more than it took to travel 300 miles upwind. What was the speed of the helicopter in still air?
---I am not sure how this problem is solved. I have done other problems somewhat similar to this, but this is a bit more difficult. An explanation would be greatly appreciated. Thank you!
Let the speed of the helicopter, in still air, be S
Then speed of wind =
Time it took to travel downwind:
Time it took to travel upwind:
We then get:
----- Multiplying by LCD,
------- Multiplying by LCD, 16
S(S - 80) = 0
S or speed or helicopter, in still air = OR S = 0 (ignore)