SOLUTION: A Turtle and a Snail are 360 meters apart, and they start to move towards each other at 3 p.m. If the Turtle is 11 times as fast as the Snail, and they met at 3:40 p.m., find the s

Question 1028963: A Turtle and a Snail are 360 meters apart, and they start to move towards each other at 3 p.m. If the Turtle is 11 times as fast as the Snail, and they met at 3:40 p.m., find the speed of each.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
You can think of this as one of them standing still
and the other moving at the sum of their speeds
3:40 minus 3:00 is 40 min
Convert to hrs:
hrs
Let = the speed of the snail
= the speed of the turtle
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and

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The speed of the snail is 45 m/hr
The speed of the turtle is 495 m/hr
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check answer:
Equation for the snail:

Equation for the turtle:

----------------

m
OK
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