# SOLUTION: The height of an object thrown upward with an initial velocity of 134 feet per second is given by the formula h = -16t2 + 134t, where t is the time in seconds. How long will it tak

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 Question 102380: The height of an object thrown upward with an initial velocity of 134 feet per second is given by the formula h = -16t2 + 134t, where t is the time in seconds. How long will it take the object to reach a height of 67 feet? Answer by stanbon(57282)   (Show Source): You can put this solution on YOUR website!The height of an object thrown upward with an initial velocity of 134 feet per second is given by the formula h = -16t2 + 134t, where t is the time in seconds. How long will it take the object to reach a height of 67 feet? ------------------------ Let h = 67 and solve for "t". -16t^2+134t-67 = 0 Use the quadratic formula to get: t = [-134 +- sqrt(134^2-4*-16*-67)]/(-32) t = [-134 +- sqrt(13668)]/(-32) t = [-134 +- 116.91]/(-32) t = 7.841 (time on the way down to the ground) or t=0.534 (time on the way up from the ground) =========================== Cheers, Stan H.