SOLUTION: The height of an object thrown upward with an initial velocity of 134 feet per second is given by the formula h = -16t2 + 134t, where t is the time in seconds. How long will it tak

Question 102380: The height of an object thrown upward with an initial velocity of 134 feet per second is given by the formula h = -16t2 + 134t, where t is the time in seconds. How long will it take the object to reach a height of 67 feet?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The height of an object thrown upward with an initial velocity of 134 feet per second is given by the formula h = -16t2 + 134t, where t is the time in seconds. How long will it take the object to reach a height of 67 feet?
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Let h = 67 and solve for "t".
-16t^2+134t-67 = 0
Use the quadratic formula to get:
t = [-134 +- sqrt(134^2-4*-16*-67)]/(-32)
t = [-134 +- sqrt(13668)]/(-32)
t = [-134 +- 116.91]/(-32)
t = 7.841 (time on the way down to the ground)
or t=0.534 (time on the way up from the ground)
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Cheers,
Stan H.
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