SOLUTION: A baseball player throws a ball upward. The height h of the ball (in feet) t seconds after the ball is released is given by h= -16t squared + 22t +78.
What is the initial height
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Question 1019314: A baseball player throws a ball upward. The height h of the ball (in feet) t seconds after the ball is released is given by h= -16t squared + 22t +78.
What is the initial height of the ball in feet?
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
The initial height is when t = 0 seconds.
Since we are given that
h(t) = -16t^2 + 22t + 78
we have
h(0) = 78 feet
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