SOLUTION: The length of a rectangle is 5 cm greater than twice the width. The area is 33 cm squared. find the dimensions
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Question 1015718: The length of a rectangle is 5 cm greater than twice the width. The area is 33 cm squared. find the dimensions
Answer by 428225(90) (Show Source): You can put this solution on YOUR website!
If you let x = the width of the triangle then the length = 2x+5
You know that the area is 33 therefore you need to multiply the width and length together.
x(2x+5)=33
2x^2+5x-33=0
Solve this quadratic to find the answer (Remember that width and length cannot be negative).
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